The scores of a high school entrance exam are approximately normally distributed with a given mean mc023-1.jpg = 82.4 and standard deviation mc023-2.jpg = 3.3. What percentage of the scores are between 75.8 and 89?
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Answer:
95.44 percentage of the scores are between 75.8 and 89
Step-by-step explanation:
z score = (value - mean)/standard deviation
mean = 82.4
value = 75.8. & 89
standard deviation= 3.3
z = (75.8 - 82.4)/3.3 = -6.6/3.3 = -2
z = (89-82.4)/3.3 = 6.6/3.3 = 2
z score - 2 = 2.28%
z score 2 = 97.72
% between these two score / z values
= 97.72-2.28
= 95.44%
95.44 percentage of the scores are between 75.8 and 89
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