The seats are arranged in rows in an auditorium. Each row has 5 more seats than the row in front. The 15th row from front has 82 seats. which row has 97 seats?
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Answered by
1
Answer:
2.here d=5
a15 = a+14d=82
solving a=12
an=a+(n-1)*d
97=12+(n-1)*5
97-12=5n-5
90=5n
n=90/5=18
so 18th row has 97 seats.
Answered by
0
Answer:
d=5
t 15=82
t 15=a+14d
a+14*5=82
a+70=82
a=12----------------(1)
tn=97
tn=a+(n-1) d
97=12+(n-1) 5( putting value of a from (1)
85=(n-1) 5
85/5=n-1
17=n-1
18=n (ans)
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