The second, 31 st and the last terms of an A.P. are
31/4, ½ and – 13/2 respectively. Find the number of
terms.
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Answer:
Step-by-step explanation: a+d = 31/4----------1
a+30d=1/2-----------2
a+(n-1)d = -13/2--------------------3
from 1 and 2 we have, a=8,d=-1/4
substituting these values in 3,
we have n=59
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