the second and 7 terms of an ap are 10 and 45 respectively find the 10th term
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hope this helps you.
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sayanelvista:
thanks man
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7
Hey friend..!! here's your answer
_________________________
an = a + ( n-1) d
So ,
a2 = a + (2 - 1 ) d
a + d = 10________(1)
Similarly ,
a + 6d = 45_________(2)
Solve equation 1 and 2
from eq 1
a = 10 - d__________(3)
Put the equatiom 3 in 2
(10-d) + 6d = 45
5d = 45 - 10
5d = 35
d = 7
Put the value of d in eq. 3
a = 10 - (7)
a = 3
a = 3 , d = 7
We need to find 10th term of AP
So n = 10
an = a + ( n - 1) d
an = 3 + ( 10 - 1)7
an = 3 + 63
an = 66
So that 10th term of AP is 66
___________
#hope its help
_________________________
an = a + ( n-1) d
So ,
a2 = a + (2 - 1 ) d
a + d = 10________(1)
Similarly ,
a + 6d = 45_________(2)
Solve equation 1 and 2
from eq 1
a = 10 - d__________(3)
Put the equatiom 3 in 2
(10-d) + 6d = 45
5d = 45 - 10
5d = 35
d = 7
Put the value of d in eq. 3
a = 10 - (7)
a = 3
a = 3 , d = 7
We need to find 10th term of AP
So n = 10
an = a + ( n - 1) d
an = 3 + ( 10 - 1)7
an = 3 + 63
an = 66
So that 10th term of AP is 66
___________
#hope its help
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