the second and fourth terms of AP are 12 and 20 respectively find the sum of first 25 terms of the a.p
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A2 = 12
A4 = 20
A2 = a+d = 12
A4 = a+3d = 20
A4-A2 = 20-12 = a+3d-a-d
8 = 2d
d = 4
a = 12-d = 12-4 = 8
Sum of 25 terms = n[2a+(n-1)d]/2
= 25(8+24×4)/2 = 1300
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