The second and the fifth terms of a geometric sequence are 2 and 1/32 respectively. Find its common ratio and its first term.
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The ninth term of 22a geometric is=arn−122
where a is the first term and r, the common ratio.
⇒second term =ar1=750→(1)
⇒fifth term =ar4=−6→(2)
To find r, divide ( 2) by ( 1)
⇒ar4ar=−6750
⇒r3=−1125⇒r=−15
Substitute this value into ( 1) to find a
⇒a×−15=750
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