The second angle of a triangle is three times as large as the first. The measure of the third angle is 40 degrees greater than that of the first angle. How large are the three angles?
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Let the 1st angle be x
The 2nd angle is equal to 3x
The 3rd angle is equal to x + 40
Because of angle sum property for triangles
x + 3x + x + 40 = 180°
You now transpose ( move over ) 40 and add the like terms
5x = 180° - 40° = 140°
Now, you transpose 5
x = 140° ÷ 5 = 28°
Therefore 1st angle is equal to 28°
2nd angle is equal to 28 × 3 = 84°
3rd angle is equal to 28 + 40 = 68°
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