Question

The second angle of a triangle is twice as large as the first. The measure of

the third angle is 20 degrees greater than the first. How large are the angles?​

Answer 1

Step-by-step explanation:

Let the first angle be x.

Second angle= 2x

Third angle= x+20

Sum of all angles of triangle= 180°

x+2x+(x+20)=180°

x+2x+x+20=180°

4x+20=180°

4x=180°-20

4x=160°

x=160÷4

x=40°

First angle= 40°

Second angle= 40°×2=80°

Third angle=40°+20°=60°

Hope it helps

Answer 2

$\huge \fbox\colorbox{lightblue}{Hey...}$

_________________________

Let the first angle be x,

Let the first angle be x, the second angle be 2x and,

Let the first angle be x, the second angle be 2x and, the third angle be +20.

:. x+2x +(x+20) = 180. [angle sum property]

➭ 4x+20 = 180

➭ 4x = 160

➭ x = 160/4

➭ x = 40

So, the first angle = 40°,

the second angle = 80°and,

the third angle. = 60°

Hence, the largest angle = 80°

_________________________

Thanks...