Question

The second digit of a three digit number is 1 and the sum of all the digits is 16. If the difference between the
place values of hundreds digit and units digit is 692, then what is the product of all the three digits ?​

Answer 1

Answer:

Let the hundreth's digit be x

Then unit's digit =x/4and ten's digit =3x/4

Given x+x/4+3x/4=16⇒4x+x+3x/4=16

⇒2x=16⇒x=8

∴ Ten's digit =3×8/4=6, unit's digit =8/4=2

∴ Required number =100×8+10×6+2

=800+60+2=862

Step-by-step explanation:

hope it helps..