Physics, asked by ps3110090, 6 months ago

The second equation of motion for a freely falling body starting from rest is

Answers

Answered by sanjaydalvi620
3

Answer:

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Answered by ak472216
0

Answer:

h=ut+1/2gt^2

Explanation:

since the second equation of motion is s=ut+1/2at^2 and for a freely falling body s=height(h) and a=acceleration due to gravity (g)

^ means power

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