the second hand of a watch has 6 CM length the speed of the tip and the magnitude of the differences in the velocity of it at any two perpendicular position will be respectively
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The second hand of a watch has 6 CM length the speed of the tip and the magnitude of the differences in the velocity of it at any two perpendicular position will be respectively
So to find out the solution to the problem
v=rω=r×2πT=0.06×2π60=6.28mm/s
Magnitude of change in velocity =|v2−→−v1−→| =v21+v22−−−−−−√=8.88mm/s (As v1=v2=6.28mm/s)
Thus, the answer is 6.28 and 8.88 mm/s
kartikpatelpatan:
v=rω=r×2πT=0.06×2π60=6.28mm/s Magnitude of change in velocity =|v2−→−v1−→| =v21+v22−−−−−−√=8.88mm/s (As v1=v2=6.28mm/s)
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