Question

The second hand of a watch is 1.5cm long. Find linear speed of a point on second hand at a distance pf 0.5 cm from the tip.

Answer 1

Answer:

Seconds HAND of watch completes 1 revolution in 60 sec ( 1min).

Time = t=60 sec

The length of seconds HAND of watch will be it's radius

r=1.5cm =1.5/100=0.015 m

DISTANCE covered = 2 * pi* r

= 2* 3.14 *0.015

Speed = distance/ time

= 2*3.14*0.015/60

=0.00157 m/ s

= 1.57 x 10 ^-3 m/s.

Therefore , speed of the tip of second's hand of a watch of length 1.5 cm is 1.57 x 10 ^-3 m/s.

Explanation: