Chemistry, asked by shezaahmed6200, 11 months ago

The second ionization potential in electron volt for oxygen and fluorine atoms are respectively given by

Answers

Answered by UrvashiBaliyan
12

Answer:

Answer:

The second ionization potentials of oxygen and fluorine atoms are 38.3 eV and 35.1 eV respectively. The electronic configuration of O+ ion is 1s22s22p3 whereas that of O2+ ion is 1s22s22p2. Thus, during ionization, the stable configuration of half filled 2p orbital is broken. This requires high energy.

Answered by Manasirao
9

Answer:

38.3,35.1

Explanation:

As the electronic configuration of O+ ion is 1s^2 2s^2 2p^3

And that of O2+ is 1s^2 2s^2 2p^3

Thus, during ionization, half 2p orbital is broken which requires high energy

And..

The electronic configuration of F+ ion is 1s^2 2s^2 2p^4

And that of F2+ is 1s^2 2s^2 2p^3

Thus,during ionization,the stable configuration of half filled 2p orbital is formed which requires less energy

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