The second line of Lyman series of H coincides with the last line of paschen series of an ionic species
X. Find X assuming Rydberg constant to same for both H and X.
(A) Li2+ ion
(B) Li* ion
(C) Heion
(D) He2+ ion
Answers
Answered by
4
Answer:
For Hydrogen, 2
nd
line of Lyman series: n=3
For 6
th
line of Paschen series: n=9
Z H 2
( 11 - 321 ) = z
X2
( 321 - 921 )
98 = Z X2
×( 91 - 811 )
98 = × 81 8
Z×2 = 9
Z × 9
(Li + 2 )
Similar questions