Question

The second member of Lyman series in
hydrogen spectrum has wavelength 5400 Aº.
Find the wavelength of first member​

Answer 1

Answer:

Explanation:

It is just an example do it yourself

We have formula ,

Here λ is wavelength , R is Rydberg constant i.e., Rh = 109737 cm⁻¹

For Lyman series ni = 1 and nf = 2, 3, 4, ....... ∞

But question is saying about 2nd line of Lyman series

means , ni = 1 and nf = 3

So, 1/λ = 109737 cm⁻¹ × (1)² [ 1/1² - 1/3² ] [ for Hydrogen Spectra Z = 1 ]

= 109737 × [1 - 1/9 ]

= 109737 × 8/9 cm⁻¹

= 877896/9cm⁻¹

Now, λ = 9/877896 cm = 1.025 × 10⁻⁷ m = 102.5 nm