The second order Bragg diffraction of X rays with lamda=1.00 A from a set of parallel planes in a metal occurs at an angle 60 . The distance between the scattering planes in the crystal is
Answers
Answered by
3
Answer:
The Bragg's equation is 2dsinθ=nλ
d is the distance between the scattering planes in the crystal.
θ is the angle of diffraction.
n is the order of diffraction.
λ is the wavelength of X rays.
2d× sin60
0
=2×1A
o
d=1.15A
o
The distance between the scattering planes in the crystal is d=1.15A
o
________________________&_
please follow me and add me to your brain list
Similar questions