Question

The second term from the end of the A.P. 5, 8, 11,....47 is​

Answer 1

The second term from the end of the A.P. 5, 8, 11,....47 is​ 44.

Given A.P. series, 5, 8, 11,....47

a = 5

d = 8 - 5 = 3

an = 47

Formula, an = a + (n-1) d

47 = 5 + (n-1) 3

47 - 5 = 3n - 3

42 + 3 = 3n

45 = 3n

n = 15

The second term from the end of the series is given by,

a(n-1) = a + [ (n-1) - 1 ] d

= 5 + [ (15-1) - 1 ] 3

= 5 + 13 × 3

= 5 + 39

= 44

a(n-1) = 44

Answer 2

The second term from the end of the A.P is 44.

Step-by-step explanation:

Common difference of the A.P.

d = 8 - 5 = 3

If we starting from the end,

d = -3

first term (a) = 47

General nth term of A.P:

$a_n=a+(n-1)d$

$a_2=47+(2-1)(-3)$

$a_2=47+(1)(-3)$

$a_2=47-3$

$a_2=44$

The second term from the end of the A.P is 44.

To learn more...

1. Is 51 term of an ap 5,8,11,14

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2. The second term from the end of the A.P. 5, 8, 11, ..., 47 is

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