The second term of an arithmetic sequence is 18 and its fourth term is 32.Write its third and first terms
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Answer:
3rd term = 25 and 1st term = 11.
Step-by-step explanation:
a + d = 18 - (1)
and a + 3d = 32 - (2)
Subtracting eq (1) from (2) , we get 2d = 14
d = 14/2 = 7
Putting d = 7 in eq (1) , we get
a + 7 = 18
a = 18 - 7
a = 11
Now the third term = a + 2d = 11 + 2 (7)
= 11 + 14
= 25
and first term = a = 11.
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