the second term of an arithmetic sequence is 7.the sum of the first four terms in the arithmetic sequence is 12.find the first term and the common difference of the sequence
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YOUR ANSWER
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a2 = 7
a+d = 7
a = 7-d
a4 =12
n/2(2a+(n-1)d)=12
4/2(2(7-d)+(4-1)d)=12
14-2d+4d-1d=12/2
14+d=6
d=6-14
d = -8
a= 7-(-8)
a=7+8
a=15
FIRST TERM,a =15
COMMON DIFFERENCE ,d =-8
HOPE IT WILL HELP YOU
____________________
YOUR ANSWER
↓↓↓↓↓↓↓↓
a2 = 7
a+d = 7
a = 7-d
a4 =12
n/2(2a+(n-1)d)=12
4/2(2(7-d)+(4-1)d)=12
14-2d+4d-1d=12/2
14+d=6
d=6-14
d = -8
a= 7-(-8)
a=7+8
a=15
FIRST TERM,a =15
COMMON DIFFERENCE ,d =-8
HOPE IT WILL HELP YOU
____________________
cuteipie82:
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