Question

The Second term of sequence is 8 and common difference is 3 what is the 12 term

Answer 1

Answer:

38

Step-by-step explanation:

t2 = t1 + D

where D= common difference

t1= 1st term

given,

t2=8

D = 3

8 = t1 +3

subtracting 3 on both sides

we get t1 = 5

tn = t1 + (n-1)D

t12 = t1 + 11D

= 5 + 11(3)

= 5+ 33

= 38

Answer 2

Answer:

The 12ᵗʰ term of the A.P. is 38.

Step-by-step-explanation:

We have given that,

For an AP,

t₂ = 8

d = 3

We have to find the 12ᵗʰ term of the A.P.

Now,

t₂ = t₁ + d

⇒ t₂ = a + d

⇒ 8 = a + 3

⇒ a = 8 - 3

⇒ a = 5

Now, we know that,

tₙ = a + ( n - 1 ) * d - - - [ Formula ]

⇒ t₁₂ = 5 + ( 12 - 1 ) * 3

⇒ t₁₂ = 5 + 11 * 3

⇒ t₁₂ = 5 + 33

⇒ t₁₂ = 38

∴ The 12ᵗʰ term of the A.P. is 38.