Question

the Seconds hand of a clock is 2.0 cm long. The average speed and modulus of average velocity of the tip of the seconds hand is ????NEED CORRECT ANSWER​

Answer 1

Hey Buddy

here is your answer:

In 15 second the angle it traverse is 90 degree or π/2 radian The arc length the tip travels is 2* π/2 = π cm ( Quarter of a circle = 2 π R / 4 = π cm ) Hence the average speed of the tip = distance / time = (π/ 15) cm /s 0.21 cm /s To find the modulus of average velocity Average velocity = displacement / time = The displacement is the hypotenuse of the right angled triangle of side 2 cm Displacement = √ ( 2² + 2²) = 2.83 cm Average velocity = 2.83 / 15 = 0.19 cm /s

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Answer 2

$\huge\underline{\overline{\mid{\bold{\pink{Question-}}\mid}}}$

A clock has its second hand2.

0 cm long . Find the average

speed and

modulus of average velocity of

the tip of the

second hand in 15s.

Options:-

$a) \frac{\pi}{15} cm {s}^{ - 1} ,( \frac{ \sqrt[2]{2} }{15} cm {s}^{ - 1} )$$</p><p></p><p>b) \frac{\pi}{2} cm {s}^{ - 1},( \frac{ \sqrt{2} }{15} cm{s}^{ - 1})$$</p><p></p><p>c) \frac{2\pi}{15} cm {s}^{ - 1}  ,( \frac{ \sqrt{2} }{15} cm{s}^{ - 1})$$</p><p></p><p>d)\frac{\pi}{15} cm {s}^ { - 1},( \frac{ \sqrt{2} }{15} cm{s}^{ - 1})$

$\huge\mathscr\red{Given}$

Length l = 2.0 cm

Time t = 15 s

Sorry, I can't type the Solution as I edited and not able to write equations.

Any ways I took an LaTeX App and Wrote.

The Solution in Attachment ↑

${\huge{\fcolorbox{aqua}{navy}{\fcolorbox{yellow}{blue}{\bf{\color{yellow}{Final Answer:-}}}}}}$

$a) \frac{\pi}{15} cm {s}^{ - 1} ,( \frac{ \sqrt[2]{2} }{15} cm {s}^{ - 1} )$