Question

the sector in the given image is half of a quarter circle. the radius of the sector is 10 CM. Of OT rotates 90 degree clockwise about it centre what is the total area swept by it​

Answer 1

Answer:

first 90 x 10 is what answer total answer will you get

Answer 2

Step-by-step explanation:

one quarter sector has mass M.

hence complete disc has mass 4m.

MI of disc rotating about line perpendicular to plane and passing through centre = [MR2 / 2]

here MI of complete disc = 4m(R2/2) = 2MR2

hence by symmetry, for quarter of disc,

MI = (1/4) (2MR2) = [(MR2) / 2]