Chemistry, asked by jasjasiijafren, 6 months ago

The selection of reducing agent depends on the thermodynamic factor : Explain with an example.​

Answers

Answered by muskanmishra115
1

Answer:

comments me in my ID I will definitely give your answer

Explanation:

follow me I will definitely give you follow back

Answered by Ashwanthraj
0

Explanation:

From the Ellingham diagram, it is clear that metals for which the standard free energy of formation (∆fG0) of their oxides is more negative can reduce the metal oxides for which the standard free energy of formation (∆fG0) of oxides is less negative. Thermodynamic factor has a major role in selecting the reducing agent for a particular reaction. Only that reagent will be preferred which will lead to decrease in the free energy (AG°) at a certain specific temperature. E.g – Carbon reduce ZnO to Zn but not CO. ZnO + C → Zn + CO …………..(1) ZnO + CO → Zn + CO2 ………………(2) In the first case, there is increase in the magnitude of ∆S° while in the second case, it almost remains the same. In other words, ∆G° will have more negative value in the first case, when C is the reducing agent then in the second case when CO acts as the reducing agent. Therefore, C is a better reducing agent.

Similar questions