The self-induced emf of a coil is 20 volts. When the current in it is changed at uniform rate from 10A to 20A in 1s, the change in the energy of the inductance is:
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Answer:
437.5 J
Explanation:
L
dt
di
=25
L×
1
15
=25
L=
3
5
H
ΔE=
2
1
×
3
5
(25
2
−10
2
)=
6
5
×525=437.5J
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