Question

the self inductance of an inductor coil is 20 mH. calculate the total magnetic flux, if the corresponding current is 4 mA.​

Answer 1

Explanation:

With the flux known, the self-inductance can be found from Equation 14.3. 4, L=NΦm/I.

Answer 2

The total magnetic flux is 8 × 10⁻⁵ Wb

Explanation:

Given:

Self inductance of inductor coil L = 20 mH

Corresponding current i = 4 mA

To find out:

Total magnetic flux ∅

Solution:

If N be the number of turns

Then we know that

$N\phi=Li$

Taking N = 1

$\phi=Li$

$\implies \phi=20\times 10^{-3}\times 4\times 10^{-3}$

$\implies \phi=8\times 10^{-5}$ Wb

Hope this answer is helpful.

Know More:

Q: A magnetic flux of 5 micro weber is linked with a coil when a current of 1mA flows through it . Calculate self inductance of the coil.

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