Question

The selling price of 10 tables is equal to the cost
price of 8 tables find the loss or
profit percent​

Answer 1

Step-by-step explanation:

let's

SP of 10 table is 10 rupees.

SP of 1 table is 1 rupees.

and

CP of 8 table is 10 rupees

CP of 1 table is 10/8= 5/4 rupees

CP is greater than SP, so he loss,

he loss in 1 table is 5/4 - 1 = 1/4 rupees

in 5/4 he loss. 1/4

in 100 he loss 1/4×4/5×100=20%

in short

he loss 2/10×100=20%

Answer 2

$\huge\pink{Answer}$

SP of $10$ tables =CP of $8$ tables

Let CP of $1$ table = ₹ $1$

then CP of $8$ tables

SP of $10$ tables=₹ $8$ (∴ CP of $8$ = SP of $10$)

SP of $1$ tables=₹$\frac{8}{10}$

⇒ ₹$\frac{4}{5}$= ₹$0.8$

Since CP ≥ SP

∴ we have lose

loss=CP-SP

⇒₹$1$-₹$0.8$

=₹$0.2$

Loss %=$\frac{loss}{CP} *100$

⇒$\frac{0.2}{1} *100$

⇒$\frac{02}{1*10} *100$

⇒$\frac{02}{10}*100$

⇒$02*10=20$

⇒$20$%

Hope It Helps