Question

the semi circular sheet of metal of diameter 28 cm is bent to form an open conical cup.find the capacity of cup.

Answer 1

Let r cm and R cm be the radius of the semi-circular sheet and base of the conical cup respectively.

Suppose the depth of the conical cup is H cm.

Given, 2r = 2.8 cm

⇒ r = 14 cm

When the semi-circular sheet of metal is bent into an open conical cup, then 

Slant height of the cone, L = Radius of the semi-circular sheet = 14 cm

Circumference of base of cone = πr

∴ 2πr = πr = 14π cm

⇒ 2R = 14 cm

⇒ R = 7 cm

Slant height of the cone, L = 14 cm



⇒ 49 cm2 + H 2 = (14 cm)2 = 196 cm2

⇒ H 2 = 196 cm2 – 49 cm2 = 147 cm2



Capacity or volume of the conical cup = 

Answer 2

Step-by-step explanation:

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