the semi perimeter of a right angle triangle is 24 cm if the hypotenuse is 20 cm what is the area of triangle
Answers
Answer:
Area of the triangle is 96 cm².
Step-by-step explanation:
Let the height be 'x' and base be 'y'. As the other side(hypotenuse) is 20 cm.
∴ Semi-perimeter = (x + y + 20)/2
24 = (x + y + 20)/2
48 = x + y + 20
28 = x + y ...(1)
Given, hypotenuse = 20 cm. Using Pythagoras theorem,
⇒ x² + y² = 20²
⇒ x² + y² = 400 ...(2)
Square on both sides of (1):
⇒ (x + y)² = 28²
⇒ x² + y² + 2xy = 784
⇒ 400 + 2xy = 784 [from (2)]
⇒ 2xy = 384
⇒ xy = 192 ...(3)
∴ Area = 1/2 * height * base
= 1/2 * x * y
= 1/2 * xy
= 1/2 * 192 [from (3)]
= 96 cm²
Given :-
- The semi perimeter of a right angle triangle is 24 cm if the hypotenuse is 20 cm.
To Find :-
- What is the area of triangle?
Solution :-
- Let height of triangle be m
- And base of triangle be n
Here, it is given that hypotenuse of right angled triangle is 20 cm and we know that by pythagoras theorem;
- Hypotenuse² = Height² + Base²
Putting all values we get,
➡ 20² = m² + n²
➡ m² + n² = 400 • • • ①
Now, it is given that semi perimeter of triangle is 24 cm and we know that semi perimeter of triangle is given by;
- Semi perimeter = Perimeter/2
We can write it as;
- Semi perimeter = (Sum of all side of triangle)/2
Putting all values we get,
➡ (m + n + 20)/2 = 24
➡ m + n + 20 = 24 × 2
➡ m + n + 20 = 48
➡ m + n = 48 - 20
➡ m + n = 28
Squaring both side we get,
➡ (m + n)² = 28²
Using identity { (a + b)² = a² + b² + 2ab } in LHS we get,
➡ m² + n² + 2mn = 784 • • • ②
From ① put in ② we get,
➡ 400 + 2mn = 784
➡ 2mn = 784 - 400
➡ 2mn = 384
➡ mn = 384/2
➡ mn = 192
Now, we know that area of right angle triangle is given by;
- Area = ½ × Base × Height
Putting all values we get,
➡ Area = ½ × m × n
➡ Area = (m × n)/2
➡ Area = mn/2
Put value of mn we get,
➡ Area = 192/2
➡ Area = 96 cm²
- Hence, area of triangle is 96 cm².