The semi perimeter of a triangle is 132 cm. The product of the difference of semi perimeter and it's respective sides is 13200 cm cube. Find the area of the triangle. 2. Find the area of a regular hexagon of side a. 3. The area of an isosceles triangle is 60 square cm and the length of each one of its equal sides is 13 cm. Find its base.
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According to herons formulae the area of a triangle is 1320cm2.As 132is semi perimeter of a triangle the formulae is √(s-a)(s-b)(s-b).And by substituting the values we get √132×√132×10×10. And area of a triangle is 1/2×base×height I.e.1/2×√132×10=1320cm2.
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