Question

The semi perimeter of a triangle of sides 40.5cm 50cm, 60.5 cm is

Answer 1

Step-by-step explanation:

151 is a perimeter of the triangle...

Answer 2

Given :

• Sides of triangle : 40.5cm, 50cm, 60.5 cm

To find :

• semi perimeter of triangle

Formula used :

$\bf s = \dfrac{a + b + c}{2}$

Where:-

• a,b,c are sides of triangle
• s = semi perimeter of triangle

$\setlength{\unitlength}{10mm}\begin{picture}(20,15)\thicklines\qbezier(1,1)(1,1)(5,1)\qbezier(1,1)(1,1)(3,4)\qbezier(5,1)( 5,1)(3,4)\put(2,0.3){\bf{c }} \put(4,3){ \bf{a }}\put( 1,3){ \bf{b }}\end{picture}$

Solution :

Now we have to find out semi-perimeter of triangle whose sides are 40.5cm, 50cm, 60.5 cm.

$\setlength{\unitlength}{10mm}\begin{picture}(20,15)\thicklines\qbezier(1,1)(1,1)(5,1)\qbezier(1,1)(1,1)(3,4)\qbezier(5,1)( 5,1)(3,4)\put(2,0.3){\bf{40.5cm }} \put(4,3){ \bf{50cm }}\put( 1,3){ \bf{60.5cm}}\end{picture}$

$\implies\sf s = \dfrac{40.5 + 50 + 60.5}{2}$

$\implies\sf s =\dfrac{40.5 + 50 + 60.5}{2}$

$\implies\sf s=\dfrac{151}{2}$

$\implies\sf s=75.5cm$

Answer :

The semi perimeter of a triangle of sides 40.5cm 50cm, 60.5 cm is = 75.5 cm