Question

The semi-perimeter of a triangle with sides 9cm, 28cm and 35cm
72cm
30cm
32cm
36cm​

Answer 1

Answer:

36 cm

Step-by-step explanation:

As per the provided information in the given question, we have :

• Sides of the triangle are 9 cm , 28 cm and 35 cm.

We've been asked to calculate the semi-perimeter of the triangle.

"Semi-perimeter" , as the name suggests, it is half of the perimeter. So, in order to find the semi-perimeter of the triangle, firstly we need to calculate the perimeter of the triangle.

$\odot$ Perimeter of the triangle is the sum of all the sides of the triangle. Let us denote the perimeter of the triangle as P here.

$\longrightarrow \sf{\quad { P = (9 + 28 + 35) \; cm}}$

Performing addition.

$\longrightarrow \sf{\quad {P = 72\; cm}}$

Now, we have to calculate the semi-perimeter of the triangle. As, we know that the semi-perimeter of the triangle is half of the perimeter of the triangle. So,

$\longrightarrow \sf{\quad { Semi-perimeter = \dfrac{P}{2}}}$

Substitute the value of P.

$\longrightarrow \sf{\quad { Semi-perimeter = \dfrac{72 \; cm}{2}}}$

Now, dividing 72 by 2.

$\longrightarrow \quad \underline{\boxed {\pmb{\frak{ Semi-perimeter = 36 \; cm}} }}$

Therefore, semi-perimeter of the triangle is 36 cm.

$\rule{200}2$

Learn More :

• Area of triangle = ½bh ( b = base ; h = height )

• Area of triangle = √{s(s - a)(s - b)(s - c)} ( a,b,c are the sides of the triangle. ; s = semi-perimeter )

• Perimeter of triangle = Sum of all sides