The semi perimeter of AABC = 28cm then AF + BD + CE=
Answers
Answered by
1
Answer:
Since length of tangents from an external point to a circle are equal
Therefore
A
F
=
A
D
D
B
=
B
E
C
F
=
C
E
Since semiperimeter of
Δ
A
B
C
=
28
c
m
⇒
perimeter of
Δ
A
B
C
=
56
c
m
⇒
AB+BC+AC=
56
(
A
F
+
D
B
)
+
(
D
B
+
C
E
)
+
(
A
F
+
C
E
)
=
56
2
(
A
F
+
B
D
+
C
E
)
=
56
A
F
+
B
D
+
C
E
=
28
c
m
Answered by
2
Step-by-step explanation:
Since length of tangents from an external point to a circle are equal
Therefore AF=AD
DB=BE
CF=CE
Since semiperimeter of ΔABC=28cm
⇒ perimeter of ΔABC=56cm
⇒AB+BC+AC=56
(AF+DB)+(DB+CE)+(AF+CE)=56
2(AF+BD+CE)=56
AF+BD+CE=28cm
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