Question

The semi perimeter of ∆ABC is 16cm, and AB =8CM andBC = 11cm. What is the area of ∆ABC?​

Answer 1

Answer:

using herons formula to get answer

the third side=16×2-(8+11)=32-19=13cm

√s(s-a) (s-b) (s-c)

you can solve it

√16(16-8)(16-11)(16-13)

Answer 2

Answer

SINCE THE SEMI PERIMETER IS 16CM,THE PERIMETER IS 32CM.HENCE,

Step-by-step explanation:

AB+BC+AC=32

8+11+AC=32

AC=13CM

BY HERON'S FORMULA,THE AREA OF ANGLE ABC WILL BE;

A=ROOT s((s-a)(s-b)(s-c)

ROOT 16(16-8)(16-11)(16-13)

ROOT 16x8x5x3

8ROOT30cm^2