Question

the semi perimeter of traingle is 96 cm and its side are in the ratio 3:4:5 find area of traingle​

Answer 1

$\huge\sf{solution - }$

$\huge\bold{\underline \red{given}}$

$\bold{ \star \: semi \: perimeter \: of \: a \: \triangle \: = 96 \: cm}$

$\bold{\star \: ratio \: of \: sides = 3 \ratio \: 4 \ratio \: 5 }$

$\huge\bold{\underline \red{find}}$

$\bold{\bigstar \: area \: of \: a \: \triangle}$

$\huge\bold{\underline \purple{steps }}$

$\bold{ = \frac{(a + b + c)}{2} = 96} \\ \\ = \frac{(3x + 4x + 5x)}{2} = 96 \\ \\ = \frac{12x}{2} = 96 \\ \\ = 12x = 96 \times 2 \\ = 12x = 192 \\ \\ x = \frac{196}{12} \: \fbox{x \: = 16}$

$\underline\bold{\dagger \: on\: putting \: the \: value \: of \: x - } \\ 3x = 3 \times 16 = 48 \\ 4x = 4 \times 16 = 64 \\ 5x = 5 \times 16 = 80$

$\ddagger \: \sf{now \: we \: know \: the \: sides \: so \: lets \: find \: out \: the \: area}$

$\huge\mathfrak{formulae}$

$\bigstar \: \bold{area \: = \sqrt{s(s - a)(s - b)(s - c)} }$

$\star \: \sf{as \: semi \: perimeter \: = 96}$

$\sf\sqrt{96(96 - 48)(96 - 64)(96 - 80)}$

$\sf \sqrt{96 \times 48 \times 32 \times 16}$

$\sf\sqrt{2359296}$

$\bold{ area} \: \underline{ \fbox{= 1536}}$

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Answer 2

Answer:

Hi .

Can I get your intro please .