Question

The semi-perimeter of triangle is 132cm the product of difference of semi-perimeter and its respective sides are 13200 cm (square). Find the area of triangle ( heron's formula)....???? solve for me>>>>

Answer 1

Solution:-
Given :-  s = 132 cm and (s-a)(s-b)(s-c) = 13200 cm²
Therefore, according to the Heron's formula, 
Area of the triangle = √s(s-a)(s-b)(s-c)
Now, substituting the values, we get
Area = √132×13200
= √132×132×100
= √132×132×10×10
Area of the triangle = 132×10
Area = 1320 cm²
Answer.

Answer 2

Solution:-

Given :-  s = 132 cm and (s-a)(s-b)(s-c) = 13200 cm²

Therefore, according to the Heron's formula, 

Area of the triangle = √s(s-a)(s-b)(s-c)

Now, substituting the values, we get

Area = √132×13200

= √132×132×100

= √132×132×10×10

Area of the triangle = 132×10

Area = 1320 cm²

Answer.