the semi vertical angle of a cone is 45 degrees. then the rate of change of its volume is : a) curved surface area times the rate of change of r b) base area times the rate of change of l c) base area times the rate of change of r d)none of these
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Answered by
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Question:
the semi vertical angle of a cone is 45 degrees. then the rate of change of its volume is :
Method of Solution:
In this Question, It is given that the semi vertical angle of a cone is 45 degrees. then the rate of change of its volume .
Now,
Let the Height of cone be h cm
Let the radius of cone be r
Now, According to the Question's Statement!
We know : [tan 45° = 1]
Tan 45° = r/h
1 = r/h
[h=r] -----(1)
Volume = 1÷3πrh
From Equation (1)
Volume = 1/3πr³
Differentiate between times.
DV/dt= πr² × Dr/DT
DV/DT = It is Equal to base area
Then, Dv/Dr = (Dr/dt) => Base area
From Option...
Option C is the Correct Answer.
[base area times the rate of change of radius]
the semi vertical angle of a cone is 45 degrees. then the rate of change of its volume is :
Method of Solution:
In this Question, It is given that the semi vertical angle of a cone is 45 degrees. then the rate of change of its volume .
Now,
Let the Height of cone be h cm
Let the radius of cone be r
Now, According to the Question's Statement!
We know : [tan 45° = 1]
Tan 45° = r/h
1 = r/h
[h=r] -----(1)
Volume = 1÷3πrh
From Equation (1)
Volume = 1/3πr³
Differentiate between times.
DV/dt= πr² × Dr/DT
DV/DT = It is Equal to base area
Then, Dv/Dr = (Dr/dt) => Base area
From Option...
Option C is the Correct Answer.
[base area times the rate of change of radius]
Answered by
10
Heya mate
The answer of ur question is in pic
Option - ( C ) is the answer
hope it helps
The answer of ur question is in pic
Option - ( C ) is the answer
hope it helps
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