The semicircular sheet of metal of diameter 28cm is bent to form an open concial cup find the capacity of the cup
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For semicircle
d = 28 cm
r = 14 cm
For cone
d = 28 cm
r = 14 cm
h = 14 cm
Capacity of cone = 1/3 πr²h
= 1/3 × 22/7 × 14 × 14 × 14
= 1/3 × 22 × 2 × 14 × 14
= 1/3 × 8624
= 2874.66 cm³
Thus capacity of cone is 2874.66 cm³ .
HOPE IT IS MOST HELPFUL!!!!!!!!!!!!!!
d = 28 cm
r = 14 cm
For cone
d = 28 cm
r = 14 cm
h = 14 cm
Capacity of cone = 1/3 πr²h
= 1/3 × 22/7 × 14 × 14 × 14
= 1/3 × 22 × 2 × 14 × 14
= 1/3 × 8624
= 2874.66 cm³
Thus capacity of cone is 2874.66 cm³ .
HOPE IT IS MOST HELPFUL!!!!!!!!!!!!!!
1Rajrohit1:
how the cone of radius is equal to height
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