The separation between the consecutive dark fringes in a Young's double slit experiment is 1⋅0 mm. The screen is placed at a distance of 2⋅5 m from the slits and the separation between the slits is 1⋅0 mm. Calculate the wavelength of light used for the experiment.
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Answer:
Given that, β=1 mm=10
−3
m,D=2.5 m and d=1 mm=10
−3
m
So, 10
−3
m=
10
−3
25×λ
⇒λ=4×10
−7
m=400 nm.
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In Young's double slit experiment the separation d between the slits is 2mm, the wavelength λ of light used is 5896Ao and distance D between the screen and slits is 100cm. It is found that the angular width of the fringes is 0. 20o. To increase the fringe angular width to 0.
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