Physics, asked by raghavgoel518, 8 months ago

The separation between the plates of a capacitor of capacitance 2uF is 4 mm. Initially, there is air
between the plate's. If two dielectric slabs of area of cross-section same as the capacitor, thickness 2 mm
each, and dielectric constant 3 and 5 respectively are introduced, the capacitance becomes (in 1F):
(A) 4
(B) 7.5
(C)
8
(D) 15

Answers

Answered by NishantRaj7
0

Explanation:

The separation between the plates of a capacitor of capacitance 2uF is 4 mm. Initially, there is air

between the plate's. If two dielectric slabs of area of cross-section same as the capacitor, thickness 2 mm

each, and dielectric constant 3 and 5 respectively are introduced, the capacitance becomes (in 1F):

(A) 4

(B) 7.5

(C)

8

(D) 15

an

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