Question

The separation between two deuterium atoms must be 1.0x10-14 m in order for the nuclear

force to overcome the Coulomb repulsive force. The charge of proton is 1.6x10-19 and Coulomb

constant Kc= 1/40 = 8.99x109

N.m2/C2

. The height of repulsive potential barrier is between

two deuterium atoms is

a. 140 MeV

b. 0.14 MeV

c. 0.07 Mev

d. 1.6x10-19 J​

Answer 1

Answer:

b is correct answer beacuse