Question

The separation between two masses is reduced to one-third. How is the magnitude of gravitational force between them aaffected???????

anyone please help.

Answer 1

Answer:

The gravitational force is directly proportional to the product of the masses and inversely proportional to square of the distance.

F=

r 2

G×m

1

×m

2

Hence, as two of the masses are reduced by half it becomes four times of the original force.

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Answer 2

Answer:

If the separation between two masses is reduced to one-third, the magnitude of the gravitational force between them will become 9 times.

Explanation:

If we consider two objects of masses, m1 and m2 then their separation can be represented as r.

Then according to Newton's law of gravitation,

Any particle of matter in the cosmos will gravitate toward any other particle with a force that varies directly as the product of their masses and inversely as the square of their separation, according to Newton's law of gravity.

It is mathematically expressed as-

F = Gm₁m₂/r² where G represents the gravitational constant

If the distance between two masses is reduced to one-third then r' = r/3

Then, newtons law of gravitation becomes-

F' = Gm₁m₂/r'²

F' = Gm₁m₂/(r/3)²

F' = 9Gm₁m₂/r²

We have, F = Gm₁m₂/r²

Therefore, F' = 9F

The magnitude become 9 times.

Thus, If the separation between two masses is reduced to one-third, the magnitude of the gravitational force between them will become 9 times.

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