Question

the separation energy of the electron present in the shell n=3 is 1.51 eV. what is the energy in the first excited state​
plz help

Answer 1

Answer:

E= 13.6eV

Explanation:

The formula for energy of nth excited state is given as :-

E=13.6(z^2)/n^2

Refer the attachement for detailed solution

Hope this answer helped you ✌