Question

The sequence -10, -6, -2, 2, . . .
(A) is an A.P., Reason d = -16
(B) is an A.P., Reason d = 4
(C) is an A.P., Reason d = -4
(D) is not an A.P.

Answer 1

t2-t1
t3-t2


-6-(-10)= -6+10
=4

-2-(-6)=-2+6
=4
.........


And so on....
Difference (d) is same i.e 4 so answer is B

Answer 2

Answer:

(B) is an A.P., Reason d = 4

Step-by-step explanation:

We have given the sequence,

-10, -6, -2, 2, . . .

Lets's just consider

a1 = -10

a2 = -6

a3 = -2

a4 = 2

now, we can see that

a2 - a1 = -6- (-10) = 4

a3 - a2 = -2-(-6) = 4

a4 - a3 = 2 - (-2) = 4

Since we can see that a2 - a1 = a3 - a2 = a4- a3 = d = 4

Hence, we can say that given sequence in in A.P with common difference 4