the sequence 2, 3, 5, 6 a, lo consiste of all natural numbers that are neither perfect squares note non perect cubes. Find the 76th term of this sequence
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87
as between 1 and 76 there are 10 numbers which are either perfect square or perfect cube so the no of terms till 76 is 76-10=66th term
as we step ahead then 87 is the 10 th term after 66th term which is 76th term from starting and these are in sequence which is neither perfect square nor perfect cube.
Hence 76th term is 87
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1
Answer:
87
Step-by-step explanation:
because because total perfect square between 1 to 76 is a 10 so the answer is the 76th term of the sequence is 76 -10
=66
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