Question

*The sequence 2, 4, 6, 8, ……*

1️⃣ is an AP with d=-2
2️⃣ is an AP with d=2
3️⃣ is not AP
4️⃣ is an AP with d=4​

Answer 1

Answer:

option 2.

Step-by-step explanation:

HOPE IT HELPS YOU......

Answer 2

${\huge{\rm{\underline{\underline{Answer\checkmark}}}}}$

$\bf{Sequence}\begin{cases}\sf{2,4,6,8,...}\end{cases}$

For any sequence to be an AP , the adjacent terms must differ with a common difference .

As we can see ,

$\mapsto \: 4 - 2 = 6 - 4 = 8 - 6 = \bf2$

As the difference of all adjacent terms is constant so, it is an A.P.

$\underline{ \boxed{ \sf{common \: diffeence = 2}}}$

So ,

Final Answer :-

$\underline{ \boxed{ \rm{option \: 2} \sf : ap \: with \: common \: difference = 2}}$

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★ Know More :-

# A.P. → It is a sequence in which adjacent terms differ with a common difference .

# It is in the form :

• a , a+d , a+2d , a+3d ,...

# n th term of an AP → a + (n-1)d

$\bull \sf \: sum \: of \: n \: terms = \frac{n}{2} \{2a + (n - 1)d \}$

or

$\bull \sf \: sum \: of \: n \: terms = \frac{n}{2} (a + n {}^{th} \: term)$

Here ,

$\mapsto \rm \: a = first \: term$

$\mapsto \rm \: d = common \: difference$

$\mapsto \rm \: n = no. \: of \: terms$

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