The sequence 27,23,18,15,11...is an a.p
Answers
Answered by
6
Ok So this is a simple Arithmetic Progressionwhere each term decreases by 4. So we have the common difference = -4
The first term of our A.P. is 27
We know that the first negative term of our A.P. will be less than 0.
Let this term be nth term.
So, nth term < 0
nth term = 27 + (n-1)-4
nth term = 27 -4n + 4 = 31 - 4n
Therefore, 31 - 4n < 0
The first term of our A.P. is 27
We know that the first negative term of our A.P. will be less than 0.
Let this term be nth term.
So, nth term < 0
nth term = 27 + (n-1)-4
nth term = 27 -4n + 4 = 31 - 4n
Therefore, 31 - 4n < 0
Similar questions