Question

the sequence a, b, 10,c,d are in AP ,then a+b+c+d​

Answer 1

Answer:

hii

Step-by-step explanation:

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Answer 2

The value of a + b + c + d = 40

Given :

The sequence a , b , 10 ,c , d are in AP

To find :

The value of a + b + c + d

Solution :

Step 1 of 2 :

Assume the terms

Here it is given that the sequence a , b , 10 ,c , d are in AP

Let us assume that

a = m - 2k , b = m - k , 10 = m , c = m + k , d = m + 2k

Where First term = m - 2k and common difference = k

Step 2 of 2 :

Find the value of a + b + c + d

a + b + c + d

= ( m - 2k ) + ( m - k ) + ( m + k ) + ( m + 2k )

= 4m

= 4 × 10

= 40

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