Question

The sequence is given as , f1=1,f2=3,fn+2=fn+fn+1, for n>=1 . How many even terms are between the first 2020 terms of that sequence?

Answer 1

Given :   The sequence is given as , f1=1,f2=3,fn+2=fn+fn+1, for n>=1  

To Find : How many even terms are between the first 2020 terms of that sequence

Solution:

f₁  = 1

f₂ = 3

f₃ = f₁  + f₂  = 1 + 3 = 4

f₄ = f₂ + f₃  = 3 + 4 = 7

f₅ = f₃ + f₄  = 4 + 7  = 11

f₆ = f₄ + f₅  = 11 + 7  = 18

f₇ = 29

f₈ = 47

f₉ = 76

Notice that for 3 terms there is one even term

2020 = 3 * 673  + 1

Hence there will 673  even terms

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Answer 2

Answer:

Step-by-step explanation:nkoyg