The series 17,21,25,29............ is an AP Find S12
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Answered by
7
Solution:
a = 17
d = 4
Formula: Sn = n/2 [2a + (n - 1)d]
Substituting the given values.
S12 = 12/2 [2(17) + (12 - 1) 4]
= 6 [34 + (11)4]
= 6 [34 + 44]
= 6 (78)
= 468
Hope this would help.
a = 17
d = 4
Formula: Sn = n/2 [2a + (n - 1)d]
Substituting the given values.
S12 = 12/2 [2(17) + (12 - 1) 4]
= 6 [34 + (11)4]
= 6 [34 + 44]
= 6 (78)
= 468
Hope this would help.
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2
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