Math, asked by wwwusmanbhat0pa2w9t, 6 months ago


The series 2+ 4 +6+8.... Is
(a) Convergent
(c) unbounded
(b) Divergent
(d) none of these​

Answers

Answered by meenakshiasnani3947
0

Answer:

(B) divergent

Step-by-step explanation:

correct answer

Answered by pulakmath007
3

The series 2 + 4 + 6 + 8 . . . . is Divergent

Given :

The series 2 + 4 + 6 + 8 . . . .

To find :

The series 2 + 4 + 6 + 8 . . . . is

(a) Convergent

(b) Divergent

(c) unbounded

(d) none of these

Concept :

 \boxed{ \:  \: \displaystyle \sf If  \:  \sum \:a_n \: converges \: then \:  \lim_{n \to  \infty }  \: a_n = 0 \:  \: }

Solution :

Step 1 of 2 :

Find nth term of the sequence

Here the given series is 2 + 4 + 6 + 8 . . . .

Let nth term of the series = aₙ

Then aₙ = 2n

Step 2 of 2 :

Test the convergence of the series

\displaystyle \sf\lim_{n \to  \infty }  \: a_n

\displaystyle \sf = \lim_{n \to  \infty }  \: 2n

\displaystyle \sf =  \infty  \ne \: 0

We know that

\displaystyle \sf If  \:  \sum \:a_n \: converges \: then \:  \lim_{n \to  \infty }  \: a_n = 0

Therefore the series is divergent

Hence the correct option is (b) Divergent

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